Posted by **natalie** on Monday, November 1, 2010 at 5:45pm.

A car is traveling at 45.0 mi/h on a horizontal highway.

(a) If the coefficient of static friction between road and tires on a rainy day is 0.100, what is the minimum distance in which the car will stop?

____ m

(b) What is the stopping distance when the surface is dry and µs = 0.602?

_____ m

- physics -
**bobpursley**, Monday, November 1, 2010 at 6:01pm
Vf^2=Vi^2+2ad

but a= force/mass= mu*mg/m= mu*g

solve for distance d.

- physics -
**Christine**, Tuesday, November 2, 2010 at 12:31pm
45 mi/h = 20.1168 m/s

ma= .100n

a = .100(g)

solving for time

v=vo + at

20.1168m/s=0+.98(t)

t=20.527s

solving for distance

d=do+vot+at^2/2

d= 0+0+.98(20.527s)^2/2

d= 206.469m

- physics -
**Christine**, Tuesday, November 2, 2010 at 12:41pm
S=u^2/2µs(g)

S=(20.1168m/s)^2/2*.602*9.8

S=34.298m

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