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December 20, 2014

December 20, 2014

Posted by **matt** on Monday, November 1, 2010 at 4:54pm.

a total of $1150 was invested, part of it at 12% and part at 11%. the total yield was $133.75. How much was invested at each rate?

- algebra -
**Reiny**, Monday, November 1, 2010 at 6:44pmfirst one:

let the amount invested at 9% be x

let the amount invested at 10% be 15000-x

.09x + .10(15000-x) = 1432

multiply each term by 100

9x + 10(15000-x) = 143200

-x = -6800

x = 6800

so $6800 were invested at 9% and $8200 at 10%

do the second question the same way.

- algebra -
**Anonymous**, Wednesday, September 7, 2011 at 4:02pm90+10(15000-x)=1432000

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