The hydroxyl radical (OH) is an important oxidizing agent in the atmosphere. At 298 K the rate constant for the reaction of OH with benzene is 1.24 10-12 cm3 molecule -1 s -1. Calculate the value of the rate constant in L mol -1 s -1.

This is what I tried:

1.24*10^-12 cm3/ molecule -1 s -1 = 0.001 L/1 cm3

=1.24E-15 L/molecule s* 6.022 x 10E23 molecules/mol
= 7.46 E8 L/mol s

Is this process correct?

ohh nvm I got it!!

yes

how did you do this?

i second jwu! i would like to know how to figured it out.

Yes, your process is correct.

To convert the rate constant from cm3 molecule -1 s -1 to L mol -1 s -1, you need to multiply the given rate constant by the conversion factor.

The conversion factor is:

1 cm3 = 0.001 L

So, to convert cm3 to L, you multiply the rate constant by 0.001 L/1 cm3.

Following your calculation:

1.24 * 10^-12 cm3 molecule -1 s -1 * 0.001 L/1 cm3 = 1.24 * 10^-15 L/molecule s

To convert from L/molecule s to L/mol s, you need to multiply the rate constant by Avogadro's number, which is 6.022 * 10^23 molecules/mol.

1.24 * 10^-15 L/molecule s * 6.022 * 10^23 molecules/mol = 7.46 * 10^8 L/mol s

So, the value of the rate constant in L mol -1 s -1 is 7.46 * 10^8 L/mol s.