How do you write
-1/9 x^-1 with a positive exponent?
also, -5 x^-2 ??
-(1/9)*x^-1.
Move x^-1 to the denominator using the opposite sign(+) This is equivalent to
multiplying the numerator and denominator by x^+1.
-1 / 9x.
-5x^-2.
Using the same procedure as in prob.1,
we get:
-5 / x^2.