Posted by on Monday, November 1, 2010 at 8:00am.
Help with this complex fraction please...
(a+2/a^2+a2)  (3a+1/a^2+2a3)
LCM is (a1) (a+2) (a+3) right? then i get stuck

math  Reiny, Monday, November 1, 2010 at 8:18am
so now change each fraction to have that LCD
[ (a+2)(a+3)  (3a+1)(a+2) ]/[(a1)(a+2)(a+3)]
expand the top and collect like terms, leave the bottom alone
=(a^2 + 5a + 6  3a^2  7a  2)/[(a1)(a+2)(a+3)]
= (2a^2  2a + 4)/[(a1)(a+2)(a+3)]
= 2(a^2 + a  2)/[(a1)(a+2)(a+3)]
= 2(a+2)(a1)/[(a1)(a+2)(a+3)]
= 2/(a+3) 
math  , Monday, November 1, 2010 at 9:16am
Thanks!