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April 21, 2014

April 21, 2014

Posted by on Monday, November 1, 2010 at 8:00am.

(a+2/a^2+a-2) - (3a+1/a^2+2a-3)

LCM is (a-1) (a+2) (a+3) right? then i get stuck

- math -
**Reiny**, Monday, November 1, 2010 at 8:18amso now change each fraction to have that LCD

[ (a+2)(a+3) - (3a+1)(a+2) ]/[(a-1)(a+2)(a+3)]

expand the top and collect like terms, leave the bottom alone

=(a^2 + 5a + 6 - 3a^2 - 7a - 2)/[(a-1)(a+2)(a+3)]

= (-2a^2 - 2a + 4)/[(a-1)(a+2)(a+3)]

= -2(a^2 + a - 2)/[(a-1)(a+2)(a+3)]

= -2(a+2)(a-1)/[(a-1)(a+2)(a+3)]

= -2/(a+3)

- math - , Monday, November 1, 2010 at 9:16am
Thanks!

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