Algebra
posted by lee .
Hello Reiny, please check these problems for me and if they are not right WOULD YOU PLEASE HELP ME WITH THE CORRECT ONES THANKS!!!
1. Slove for X, wher X is the real number, square root 5x + 9= square root 9x + 13= 27
2. Find the value: ^3 square root 27= 9
3. Write the following in simplified radical form ^4 square root 80= 4
PLEASE HELP QUICKLY!!

1 . I assume you meant
√(5x+9) = √(9x+13)
if so, then square both sides
5x + 9 = 9x + 13
4x = 4
x = 1, the answer checks in my equation
2. I can't figure out what you are saying.
are you finding the cuberoot of 27 ?
if so, the cuberoot of 27 = 3
3 again, is that supposed to the fourth root of 80 ?
80^(1/4) = (16)^(1/4) (5)^(1/4)
= 2 times cuberoot of 5 
last line should have said
2 times fourthroot of 5 
THANKS AGAIN Reiny!!