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March 29, 2017

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A soccer ball is kicked into the air at an angle of 38 degrees above the horizontal. The initial velocity of the ball is +30.0m/s. How long is the ball in the air?

-What is the maximum height reached by the ball?
-What is the horizontal distance traveled by the ball?

  • physics - ,

    Vi = 30 sin 38

    h = Ho + Vi t - 4.9 t^2
    h = 0 at ground
    so
    0 = 0 + Vi t - 4.9 t^2
    t (Vi-4.9 t) = 0
    t = 0 (it started at ground
    t = Vi/4.9 when it hit ground again

    max h is when v = 0
    v = Vi -9.8 t
    0 = Vi -9.8 t
    t = Vi/9.8 at top *** this should be half the whole time in the air***
    h = 0 +Vi t - 4.9 t^2
    using that t which should be half the total t

    u = 30 cos 38
    d = u t where t is the total time in the air (not the half time you used for part B)

  • physics - ,

    3.766 seconds, 25.544 m, 88.886 m,

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