Posted by Esora on Sunday, October 31, 2010 at 9:38pm.
A soccer ball is kicked into the air at an angle of 38 degrees above the horizontal. The initial velocity of the ball is +30.0m/s. How long is the ball in the air?
What is the maximum height reached by the ball?
What is the horizontal distance traveled by the ball?

physics  Damon, Sunday, October 31, 2010 at 9:47pm
Vi = 30 sin 38
h = Ho + Vi t  4.9 t^2
h = 0 at ground
so
0 = 0 + Vi t  4.9 t^2
t (Vi4.9 t) = 0
t = 0 (it started at ground
t = Vi/4.9 when it hit ground again
max h is when v = 0
v = Vi 9.8 t
0 = Vi 9.8 t
t = Vi/9.8 at top *** this should be half the whole time in the air***
h = 0 +Vi t  4.9 t^2
using that t which should be half the total t
u = 30 cos 38
d = u t where t is the total time in the air (not the half time you used for part B)

physics  swag, Thursday, November 5, 2015 at 8:54pm
3.766 seconds, 25.544 m, 88.886 m,
Answer This Question
Related Questions
 physics  a soccer ball is kicked into the air at an angle of 38 degrees above ...
 physics  a soccer ball is kicked into the air at an angle of 38 degrees above ...
 physics  a soccer ball is kicked into the air at an angle of 38 degrees above ...
 Physics  A soccer player kicks a ball into the air at an angle of 36.0 Degrees ...
 Physics  A soccer player kicks a ball into the air at an angle of 36 degrees ...
 physics  A soccer player kicks a ball into the air at an angle of 34 degrees ...
 physics  a soccer player kicks a ball into the air at an angle of 36.0 above ...
 Physics  A tennis player hits a ball at ground level, giving it an initial ...
 Physics  2D kinematics  A soccer ball is kicked with an initial horizontal ...
 Physics  A tennis player hits a ball at ground level, giving it an initial ...
More Related Questions