What is the total kinetic energy of 1.70 moles of nitrogen gas at 30 celsius?
Please explain step by step by providing formula.
To find the total kinetic energy of a gas, we can use the formula:
KE = (3/2) * n * R * T
- KE is the total kinetic energy of the gas
- n is the number of moles of the gas
- R is the gas constant
- T is the temperature in Kelvin
Now, let's follow these steps to find the total kinetic energy:
Step 1: Convert the temperature from Celsius to Kelvin.
The formula to convert Celsius to Kelvin is:
T(K) = T(°C) + 273.15
Given T(°C) = 30, we can calculate T(K) as:
T(K) = 30 + 273.15 = 303.15 K
Step 2: Calculate the total kinetic energy using the formula mentioned earlier:
KE = (3/2) * n * R * T
Given n = 1.70 moles, R is the gas constant, and T = 303.15 K, we can calculate the total kinetic energy:
KE = (3/2) * 1.70 * R * 303.15
Unfortunately, you have not provided the value of the gas constant R. The value of R depends on the units used for pressure and volume. In SI units, the value of R is approximately 8.314 J/(mol K).
Hence, the formula for calculating the total kinetic energy of 1.70 moles of nitrogen gas at 30 Celsius is:
KE = (3/2) * 1.70 * 8.314 * 303.15 J