Posted by **valerie** on Sunday, October 31, 2010 at 7:55pm.

the speed of a cyclist reduces uniformly from 2.5 m/s to 1.0 m/s in 12 s.

(a) calculate the deceleration of the cyclist.

(b) calculate the distance travelled by the cyclist in this time

- physics -
**Kunal**, Tuesday, April 17, 2012 at 12:48pm
Sol

Accelaration=F.V-I.V/TIME TAKEN

NOW WE CAN SAY THAT,

a=0-2.5/12

a=-2.5/12

a=0.2083

- physics -
**ukra**, Monday, August 26, 2013 at 9:47am
i don't know

- physics -
**ANONYMOUS**, Thursday, June 2, 2016 at 11:27am
a) Acceleration or deceleration = Final velocity - initial velocity / Time taken

D = 1-2.5 / 12

D= -0.125

b) d = ½×(Vi + Vf) × t

where

d = displacement = ?

Vf = final velocity = 1 m/s

Vi = initial velocity = 2.5 m/s

t = time = 12 s

so

d = ½×(2.5 + 1) × 12

d = 21 m

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