could someone please check these roblems for me and if they are not rightWOULD YOU PLEASE HELP E WITH THE CORRECT ONES THANKS!!!

1. Slove for X, wher X is the real number, square root 5x + 9= square root 9x + 13= 27
2. Find the value: ^3 square root -27= 9
3. Write the following in simplified radical form ^4 square root 80= 4
PLEASE HELP QUICKLY!!
Thanks!!

Hello Reiny,I need your help a few more times, and this time if they are not right, could you please help me with the correct answers!!

THANKS

I'd be happy to help you with these problems! Let's go through each one step by step.

1. Solve for X: √(5x + 9) = √(9x + 13) = 27

To solve this equation, we need to square both sides of the equation to eliminate the square roots:

√(5x + 9) = 27
(√(5x + 9))^2 = 27^2
5x + 9 = 729

Simplifying further, we get:
5x = 720
x = 720/5
x = 144

So, the value of x that solves the equation is x = 144.

2. Find the value: ∛(-27) = 9

To solve this problem, we need to find the number whose cube is equal to -27. It's worth noting that the cube root of a number could be positive, negative, or zero.

∛(-27) = -3

So, the value of the cube root of -27 is -3.

3. Write the following in simplified radical form: ∜80 = 4

To simplify the fourth root of 80, we need to find the prime factors of 80 and group them together in pairs with exponents.

The prime factorization of 80 is: 2^4 * 5

We can group the pairs of prime factors as follows: (∜2^4) * (∜5) = 2 * ∜5 = 2∜5

Therefore, the simplified radical form of the fourth root of 80 is 2∜5.

I hope this helps! Let me know if you have any further questions.