Homework Help: physics

Posted by Corey on Sunday, October 31, 2010 at 4:14pm.

A grinding wheel 0.40 m in diameter rotates at 2200 rpm.

What is the acceleration of a point on the edge of the grinding wheel?

physics - bobpursley, Sunday, October 31, 2010 at 4:54pm
centripetal acceleration= w^2 r

w = 2PI*2200r/min*1min/60sec

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