Wednesday
March 29, 2017

Post a New Question

Posted by on .

A grinding wheel 0.40 m in diameter rotates at 2200 rpm.

What is the acceleration of a point on the edge of the grinding wheel?

  • physics - ,

    centripetal acceleration= w^2 r

    w = 2PI*2200r/min*1min/60sec

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question