Posted by lee on Sunday, October 31, 2010 at 3:41pm.
is these answers correct?
solve the equation: 2x^2 +8x  17=(x +2)^2= x=7,3
solve (v5)^263=0, where v is a real number, simplify answer as much as possible. v=3 square root 7+5,3 square root7+5
v``12.93725, 2.937254
use the quadratic formula to solve for x.
4x^2x4=0
=x=1+squar root65/8 , 1square root65/8=x``1.132782,0.882782
thank yu

math  lee, Sunday, October 31, 2010 at 3:57pm
Need help quick please!! with provious questions on checking my answers.

math  Reiny, Sunday, October 31, 2010 at 4:59pm
the first one is correct
the second is correct
third, you have a typo in your equation
the answers are correct if the equation is
4x^2  x  4 = 0

math  lee, Sunday, October 31, 2010 at 5:11pm
Thanks Reiny!!

math  lee, Sunday, October 31, 2010 at 5:42pm
could you please check this for me? Thanks
use the quadratic formula to solve for x. 4x^2x4=0
x=1+ square root 65/8, 1 square root 65/8 = x``1.132782,0.882782

math  lee, Sunday, October 31, 2010 at 5:55pm
sorry I have a few more and I need the answers quick!!
Find the value: ^3 square root 27= 9
Write the following in simlpified radical form: ^4 square root 80= 4
Solve for x, where x is real number: square 5x + 9= square root 9x + 13=27

math  lee, Sunday, October 31, 2010 at 6:06pm
SIMPLIFY:
32 3/5= 15 IS THIS CORRECT?

math  Jen, Sunday, October 31, 2010 at 6:44pm
No, 32 3/5 cannot be simplified.

math  lee, Sunday, October 31, 2010 at 6:48pm
is this correct if not can you tell me wha it is please
32 3/5= 163/5
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