Predict whether or not a precipitate will form upon mixing 75.0 mL of a NaOH solution with pOH = 2.58 with 125.0 mL of a 0.018 M MgCl2 solution. Identify the precipitate, if any.

Express as a chemical rxn

NaOH(aq) + MgCl2(aq) => NaCl(s) + MgOH(aq)
I have to balacnce it and identiy the precipitate I think its NaCl. Can you tell me what I am doing wrong with balancing?

You have the wrong formula for magnesium hydroxide. It should be Mg(OH)2.

To determine if a ppt will form or not, calculate Qsp and compare that with Ksp for Mg(OH)2.

will it be

2NaOH(aq)+MgCl2(aq)-> 2NaCl(aq)+ Mg(OH)2(s)

The balanced chemical equation for the reaction between NaOH and MgCl2 is:

2NaOH(aq) + MgCl2(aq) -> 2NaCl(aq) + Mg(OH)2(s)

In this reaction, the sodium hydroxide (NaOH) reacts with magnesium chloride (MgCl2) to form sodium chloride (NaCl) and magnesium hydroxide (Mg(OH)2).

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance it:

NaOH(aq) + MgCl2(aq) -> NaCl(aq) + Mg(OH)2(s)
2NaOH(aq) + MgCl2(aq) -> 2NaCl(aq) + Mg(OH)2(s)

In this balanced equation, we have 2 sodium (Na) atoms on both sides, 2 oxygen (O) atoms on both sides, and 2 hydrogen (H) atoms on both sides. The equation is now balanced correctly.

Regarding the precipitate, in this reaction, a precipitate of magnesium hydroxide (Mg(OH)2) will form. Sodium chloride (NaCl) remains in the aqueous (dissolved) state.

So, the correct balanced chemical equation for the reaction between NaOH and MgCl2 is:

2NaOH(aq) + MgCl2(aq) -> 2NaCl(aq) + Mg(OH)2(s)

To balance the chemical equation for the reaction between NaOH and MgCl2, follow these steps:

1. Write down the equation: NaOH(aq) + MgCl2(aq) -> NaCl(s) + Mg(OH)2(aq)
2. Count the number of atoms of each element on both sides of the equation.

On the left side:

Na: 1 atom
O: 1 atom
H: 1 atom
Mg: 1 atom
Cl: 2 atoms

On the right side:

Na: 1 atom
O: 2 atoms
H: 2 atoms
Mg: 1 atom
Cl: 1 atom

3. Determine which atoms are unbalanced. In this case, oxygen (O) and hydrogen (H) are unbalanced.

4. Balance the oxygen atoms by adding a coefficient in front of Mg(OH)2 on the right side of the equation, making it 2Mg(OH)2(aq).

The equation now becomes: NaOH(aq) + MgCl2(aq) -> NaCl(s) + 2Mg(OH)2(aq)

5. Count the number of atoms of each element again to check if it is balanced.

On the left side:

Na: 1 atom
O: 1 atom
H: 1 atom
Mg: 1 atom
Cl: 2 atoms

On the right side:

Na: 1 atom
O: 4 atoms
H: 4 atoms
Mg: 2 atoms
Cl: 2 atoms

Now, the equation is balanced.

The precipitate formed in this reaction is Mg(OH)2.