Posted by Bill on Sunday, October 31, 2010 at 11:42am.
Not a right triangle?
You know angle, or SAS.
you want the other distance (S)
I think I would start with the law of cosines:
c^2=a^2+b^2 -2ab CosC
Ok. So c^2=100^2+b^2-2(100)b Cos100 ?
c^2=100^2-x+(-12t)^2-2(100-x)(-12t) Cos100 or maybe this?
Still trying to figure this out.
Am i going in the right direction?
c2=(12t)^2+(10t)^2-2(12t)(10t)Cos100
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