Post a New Question


posted by .

At noon, ship A is 100 Kilometers due east of ship B, Ship A is sailing west at 12 k/h, and ship B is sailing S10degrees west at 10k/h. At what time will the ships be nearest each other and what time will the distance be?
(not a right triangle)?

  • Calc -

    Not a right triangle?

    You know angle, or SAS.

    you want the other distance (S)

    I think I would start with the law of cosines:
    c^2=a^2+b^2 -2ab CosC

  • Calc -

    Ok. So c^2=100^2+b^2-2(100)b Cos100 ?

  • Calc -

    c^2=100^2-x+(-12t)^2-2(100-x)(-12t) Cos100 or maybe this?

  • Calc -

    Still trying to figure this out.

    Am i going in the right direction?


Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question