Posted by Bill on Sunday, October 31, 2010 at 11:42am.
At noon, ship A is 100 Kilometers due east of ship B, Ship A is sailing west at 12 k/h, and ship B is sailing S10degrees west at 10k/h. At what time will the ships be nearest each other and what time will the distance be?
(not a right triangle)?

Calc  bobpursley, Sunday, October 31, 2010 at 11:53am
Not a right triangle?
You know angle, or SAS.
you want the other distance (S)
I think I would start with the law of cosines:
c^2=a^2+b^2 2ab CosC

Calc  Bill, Sunday, October 31, 2010 at 12:57pm
Ok. So c^2=100^2+b^22(100)b Cos100 ?

Calc  Bill, Sunday, October 31, 2010 at 1:05pm
c^2=100^2x+(12t)^22(100x)(12t) Cos100 or maybe this?

Calc  Bill, Sunday, October 31, 2010 at 2:36pm
Still trying to figure this out.
Am i going in the right direction?
c2=(12t)^2+(10t)^22(12t)(10t)Cos100
Answer This Question
Related Questions
 calculus  At noon, ship A is 100 kilometers due east of ship B. Ship A is ...
 Calc  At noon, ship A is 100 Kilometers due east of ship B, Ship A is sailing ...
 Calc  At noon, ship A is 100 Kilometers due east of ship B, Ship A is sailing ...
 calc  At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km...
 calc  At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...
 calc  At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...
 Calc  At noon, ship A is 40 nautical miles due west of ship B. Ship A is ...
 CALCULUS  At noon, ship A is 130 km west of ship B. Ship A is sailing east at ...
 calculus  At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...
 calculus  At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...
More Related Questions