Give your answer as an ordered set of numbers , , , ... Use the least possible integers for the coeffiients
Consider the following unbalanced equation for the neutralization of acetic acid:
HC2H3O2(aq)+Ba(OH)2(aq)=H2O(l)+
this has the werid sybols and I can not type it out for the a b t and s
What's a b t and s?
2HC2H3O2(aq) + Ba(OH)2(aq) ==> Ba(C2H3O2)2(aq) + 2H2O(l)
To balance the equation, we need to determine the coefficients that will ensure an equal number of each type of atom on both sides of the equation.
The unbalanced equation is:
HC2H3O2(aq) + Ba(OH)2(aq) = H2O(l) +
Let's start by counting the number of atoms on each side:
On the left side (reactants):
- 1 hydrogen (H) atom from HC2H3O2
- 2 carbon (C) atoms from HC2H3O2
- 4 hydrogen (H) atoms from HC2H3O2
- 2 oxygen (O) atoms from HC2H3O2
- 1 barium (Ba) atom from Ba(OH)2
- 2 hydrogen (H) atoms from Ba(OH)2
- 2 oxygen (O) atoms from Ba(OH)2
On the right side (products):
- 2 hydrogen (H) atoms from H2O
- 1 oxygen (O) atom from H2O
Since the number of atoms is not balanced, we can start by balancing the hydrogen (H) atoms.
On the left side, we have a total of 4 hydrogen (H) atoms. To balance this, we need 2 hydrogen (H) atoms on the right side. So, we can add a coefficient of 2 in front of H2O:
HC2H3O2(aq) + Ba(OH)2(aq) = 2H2O(l) +
Now, let's balance the oxygen (O) atoms.
On the left side, we have a total of 2 oxygen (O) atoms from the acetic acid (HC2H3O2) and 2 oxygen (O) atoms from the barium hydroxide (Ba(OH)2). This gives us 4 oxygen (O) atoms in total.
On the right side, we have 1 oxygen (O) atom from water (H2O).
To balance the oxygen (O) atoms, we need a coefficient of 4 in front of the water:
HC2H3O2(aq) + Ba(OH)2(aq) = 2H2O(l) + 4
Finally, let's balance the carbon (C) and barium (Ba) atoms.
On the left side, we have 2 carbon (C) atoms from acetic acid (HC2H3O2) and 1 barium (Ba) atom from barium hydroxide (Ba(OH)2).
On the right side, we don't have any carbon (C) atoms or barium (Ba) atoms.
To balance these, we need to add coefficients of 2 in front of HC2H3O2, and 1 in front of Ba(OH)2:
2HC2H3O2(aq) + Ba(OH)2(aq) = 2H2O(l) + 4
Therefore, the balanced equation is:
2 HC2H3O2(aq) + Ba(OH)2(aq) = 2 H2O(l) + 4