Posted by **Pierre** on Saturday, October 30, 2010 at 3:55pm.

A wire 9 meters long is cut into two pieces. One piece is bent into a square for a frame for a stained glass ornament, while the other piece is bent into a circle for a TV antenna. To reduce storage space, where should the wire be cut to minimize the total area of both figures? Give the length of wire used for each:

For the square?

For the circle?

Where should the wire be cut to maximize the total area? Again, give the length of wire used for each:

For the square?

For the circle?

- MINIMIZATION PROBLEM (CALC) -
**bobpursley**, Saturday, October 30, 2010 at 5:06pm
total area= PIr^2+ ((9-2r)/4)^2

so find r when dA/dr=0

lengths of two pieces: 2r, 9-2r

you will get two solutions, one for min area, one for max area.

- MINIMIZATION PROBLEM (CALC) -
**Anonymous**, Monday, November 14, 2011 at 1:53am
n-7w

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