Posted by Pierre on .
A wire 9 meters long is cut into two pieces. One piece is bent into a square for a frame for a stained glass ornament, while the other piece is bent into a circle for a TV antenna. To reduce storage space, where should the wire be cut to minimize the total area of both figures? Give the length of wire used for each:
For the square?
For the circle?
Where should the wire be cut to maximize the total area? Again, give the length of wire used for each:
For the square?
For the circle?

MINIMIZATION PROBLEM (CALC) 
bobpursley,
total area= PIr^2+ ((92r)/4)^2
so find r when dA/dr=0
lengths of two pieces: 2r, 92r
you will get two solutions, one for min area, one for max area. 
MINIMIZATION PROBLEM (CALC) 
Anonymous,
n7w