A force of 5.00 N to the left causes a 1.35 kg book to have a net acceleration of 0.76 m/s2 to the left. What is the frictional force acting on the book?
3.974
F=ma
m=1.35
a=0.76
Force after friction
=1.35*0.76
=1.026 N
Force applied=5 N
Therefore frictional force
=5-1.026N
=?
Well, well, well, looks like we've got a frictional force puzzle on our hands! Let me clown around with the numbers for a moment.
First, we need to know the force required to make that book accelerate. From Newton's second law (F = ma), we can rearrange the equation to find the force:
F = ma
F = (1.35 kg)(0.76 m/s²)
F = 1.028 N
So, we have a force of 1.028 N causing the book to accelerate.
Now, here comes the frictional force, sliding in like a banana peel. Since the force applied is 5.00 N to the left, and the book's acceleration is also to the left, it means that the frictional force must be in the opposite direction (to the right).
Therefore, the frictional force is 5.00 N - 1.028 N (cue the circus music) = 3.972 N to the right.
So, the clown-approved answer is that the frictional force acting on the book is 3.972 N to the right.
Hope that put a smile on your face! Let me know if you need any more clowning around with physics.
To find the frictional force acting on the book, we can use Newton's second law of motion:
Fnet = m * a
Where:
Fnet is the net force acting on the object,
m is the mass of the object,
a is the acceleration of the object.
In this case, the net force acting on the book is the force applied to the left (opposite to motion) and the frictional force acting to the right (opposite to the applied force). Therefore, Fnet = Fapplied - Ffriction.
Given:
Force applied (Fapplied) = 5.00 N to the left
Mass (m) = 1.35 kg
Acceleration (a) = -0.76 m/s^2 (negative sign indicates motion to the left)
Substituting these values into the equation, we have:
5.00 N - Ffriction = 1.35 kg * (-0.76 m/s^2)
Multiply the mass and acceleration:
5.00 N - Ffriction = -1.03 kg·m/s^2
Rearranging the equation to solve for the frictional force:
Ffriction = 5.00 N + 1.03 kg·m/s^2
Calculating the frictional force:
Ffriction = 6.03 kg·m/s^2
Therefore, the frictional force acting on the book is 6.03 N to the right.
To find the frictional force acting on the book, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, we're given the force and acceleration, and we need to find the frictional force. The equation we'll use is:
Net force = mass x acceleration
We'll rearrange the equation to solve for the net force:
Net force = mass x acceleration
Net force = 1.35 kg x 0.76 m/s^2
Net force = 1.026 N
The net force acting on the book is 1.026 N.
Since the net force is the sum of all the forces acting on the book, and we're given the applied force of 5.00 N to the left, we can subtract the applied force from the net force to find the frictional force.
Frictional force = Net force - Applied force
Frictional force = 1.026 N - 5.00 N
Frictional force = -3.974 N
The frictional force acting on the book is -3.974 N.
Note: The negative sign indicates that the frictional force is acting in the opposite direction to the applied force, which means it's acting to the right in this case.