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December 19, 2014

December 19, 2014

Posted by **sh** on Saturday, October 30, 2010 at 5:46am.

f(x)=(log(base2)x)^5

f'(x)=[5(log(base2)x)^4]/xln2

f"(x)=[20(log(base2)x)³(xln2)-(ln2+(x/2))(5(log(base2)x)^4)]/[x²(ln2)²]

for the f"(x), is g(x)=xln2? It is a product so I think it should be dealt with differently, but I am unclear on that.

Thanks

- Calculus -
**Reiny**, Saturday, October 30, 2010 at 8:05amin your f ''(x) you forgot to differentiate the log

_{2}x part , and in the second part when you differentiate xln2 you simply get ln2.

Remember ln2 is just a number so xln2 is (ln2)x , a simple term like 6x.

I had

f ''(x) = [20(log(base2)x)³(1/(xln2)(xln2)-(ln2))(5(log(base2)x)^4)]/[x²(ln2)²]

Now doesn't the xln2 at the top and bottom of the first section cancel?

check my arithmetic, too early in the morning

- Calculus -
**sh**, Saturday, October 30, 2010 at 2:45pmI have the same thing now, thanks! I thought I had to use product rule for xln2, but there's no variable in ln2, so it is accounted for a constant?

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