Posted by **hilde** on Saturday, October 30, 2010 at 4:05am.

on a level road the stopping distance for an automobile is 35.0m for an initail speed of 90 km/hr what is the stopping distance of the same automobile on a simalr road with the slope 1:10

- physics -
**bobpursley**, Saturday, October 30, 2010 at 7:42am
Assume the coefficent of friction is the same.

F=mu*Normal force=ma

a= normalforce*mu/mass

Vf^2=Vi^2+2ad

solve for mu on the level road, knowing normalforce is mg.

Then, knowingmu, look at the slope

normal force=mg*SinTheta

Vf^2=Vi^2+2mgSinTheta*mu/m * d

solve for distance.

since Theta is a small angle, SinTheta=TanTheta= 1/10

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