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chemistry

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How much of a 0.23 M NaOH solution is needed to neutralize 27 mL of a 0.85 M sulfuric acid solution? The units are mL.

Can you please explain why you did what did

Thank you

  • chemistry - ,

    well, it takes two moles of NaOH to neutralize on mole of sulfuric acid, so

    2*.23(Volumebase)=27ml*.85
    solve for volumebase

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