I'm on a test..don't get me wrong physics is hard. Ha. A 10 kg sled is pulled horizontally by a force. If the coefficient of static friction is 0.3 , what force is needed to get the sled moving at a constant velocity?

Luis only said this because he doesnt know the answer. neither did I. Im eleven. But luis your a tool.

To determine the force needed to get the sled moving at a constant velocity, we need to consider the forces acting on the sled.

In this case, the main force acting on the sled is the force of static friction (fs). The force needed to overcome static friction is referred to as the minimum force required to initiate motion (F_min). Once the sled starts moving, the force of kinetic friction will come into play, but in this scenario, we are assuming constant velocity, so kinetic friction can be ignored.

The force of static friction can be calculated using the equation:

fs = coefficient of static friction * normal force

The normal force (Fn) is the force exerted on the sled by the surface it rests on, which is equal to the weight of the sled (mg) assuming no vertical forces.

Given:
mass (m) = 10 kg
coefficient of static friction (μ) = 0.3

First, calculate the normal force:
Fn = mg = 10 kg * 9.8 m/s^2 ≈ 98 N

Next, calculate the force of static friction:
fs = μ * Fn = 0.3 * 98 N ≈ 29.4 N

Therefore, the force needed to get the sled moving at a constant velocity is approximately 29.4 Newtons.