Posted by **Surendra** on Friday, October 29, 2010 at 10:58am.

In a triangle ABC,E and F are the mid-points of AC and AB respectively. The altitude AP to BC intersects EF at Q.Prove AQ =PB.

- geometry -
**bobpursley**, Friday, October 29, 2010 at 11:20am
I would use similar triangles

First ACP ~ AFQ (use alt angle of parallel lines, and one common angle, triangles with three same angles are sim)

Then, AF=FC given midpoint.

which then, using proportion, aq=qp

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