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October 26, 2014

October 26, 2014

Posted by **Surendra** on Friday, October 29, 2010 at 10:58am.

- geometry -
**bobpursley**, Friday, October 29, 2010 at 11:20amI would use similar triangles

First ACP ~ AFQ (use alt angle of parallel lines, and one common angle, triangles with three same angles are sim)

Then, AF=FC given midpoint.

which then, using proportion, aq=qp

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