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March 26, 2017

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how many moles of Ba(OH)2 are present in 295mL of 0.400 M Ba(OH)2?

  • Chemistry - ,

    Molarity = Moles/Liters

    therefore
    Moles = Molarity x Liters
    Convert 295mL to L = 0.295L
    Moles = 0.400M x 0.295L
    = 0.118 mol Ba(OH)2

  • Chemistry - ,

    .09 mol

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