Calculate the molarity of 1.77 mol of LiCl in 30.6 L of solution.
This is for hw that's submitted online. the answer i got is 0.06 M. but it says its wrong, whyyyyy?
molarity is moles of solute per liter of solution:
M = moles/L
plug in the given values in the equation, therefore:
M = 1.77 / 30.6 = 0.0578 M
is it required to write the answer in correct number of significant figures?
if not, i think 0.06 M is acceptable ;
but if yes, it must be 0.0578 M (3 significant figures),,
hope this helps.
jai is correct. Most of these on-line databases require the correct number of significant figures and 0.06 will be counted wrong.
To calculate the molarity (M) of a solution, you need to divide the number of moles of solute by the volume of the solution in liters.
Given:
Number of moles of LiCl = 1.77 mol
Volume of solution = 30.6 L
Molarity (M) = Number of moles / Volume (in liters)
Substituting the given values into the formula:
Molarity = 1.77 mol / 30.6 L
Molarity = 0.058 M (rounded to three decimal places)
Therefore, your answer of 0.058 M is correct.
If the answer is marked wrong, there might be a different rounding or significant figure policy in place for the online homework platform you are using. Double-check the required number of significant figures or decimal places specified by your instructor or the platform, and make sure to round your answer accordingly.