February 19, 2017

Homework Help: Chemistry

Posted by Chris Sung on Friday, October 29, 2010 at 1:20am.

Alumminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+H2SO4-->Al2(SO4)+6H2O.
Which reagent is the limiting reactant when 0.500 mol Al(OH)3 and 0.500 mol H2SO4 are allowed to react?
How many moles of Al2(SO4)3 can form under these conditions?
How many moles of the excess reactant remain after the completion of the reaction?

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions