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October 31, 2014

October 31, 2014

Posted by **Chelsea** on Thursday, October 28, 2010 at 11:25pm.

find dy/dx by implicit differentiation

0 + 1 = cos(xy^2). (x)(2y)dy/dx + (y^2)(1)

1/((x)(2y)dy/dx) = cos(xy^2) + (y^2)

dy/dx = cos (xy^2) + (y^2)....

Can I just divide out the (x)(2y) and leave the dy/dx?

- calc -
**Reiny**, Thursday, October 28, 2010 at 11:31pmyou needed brackets like this

0 + 1 = cos(xy^2)*( (x)(2y)dy/dx + (y^2)(1) )

since you need to get at the dy/dx and since it is inside the bracket, you must expand

1 = 2xy(cos(xy^2))dy/dx + y^2(cos(xy^2)

1 - y^2(cos(xy^2) = 2xy(cos(xy^2))dy/dx

dy/dx = (1 - y^2(cos(xy^2))/(2xy(cos(xy^2)))

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