Friday

September 19, 2014

September 19, 2014

Posted by **khela** on Thursday, October 28, 2010 at 9:58pm.

without using l'hopitals rule

- maths -
**jai**, Thursday, October 28, 2010 at 10:01pmis the function, like this:

[sin(x-1)]/(x^2 + x - 2)

or this:

sin [(x-1)/(x^2 + x - 2)]

?

- maths -
**khela**, Thursday, October 28, 2010 at 10:10pmthe first option

- maths -
**jai**, Thursday, October 28, 2010 at 10:40pmalright then. if using L'hopital's Rule is not allowed, then recall the property:

lim (sin x)/x = 1 as x->0

therefore,

lim [sin(x-1)]/(x^2 + x - 2)

we can factor the denominator:

(x^2 + x - 2) = (x-1)(x+2)

we can then re-write the limit as:

lim [sin(x-1)]/[(x-1)(x+2)]

then we group terms, such as this:

lim {[sin(x-1)]/(x-1)} * lim (1/(x+2))

notice that the first looks like the property lim (sin x)/x = 1 as x->0 ,,

but we do shifting in x in order to have x approach 1,,

lim {[sin(x-1)]/(x-1)} as x->1 = 1

therefore, its limit is 1,, thus,

1 * lim (1/(x+2)) as x -> 1

1 * (1/(1+2))

1/3

hope this helps. :)

**Answer this Question**

**Related Questions**

maths - find the limit as x approaches 0 of the function: (e^x.sinx)/x without ...

Calculus - Find the limit. Use L'Hopitals Rule if necessary. lim (x^2+3x+2)/(x^2...

calculus - I am studying for a final exam and in our review packet we have this ...

Calculus - Find the positive integers k for which lim ->0 sin(sin(x))/x^k ...

calc - Use L’Hopital’s rule to find the limit of this sequence (n^100)/(e^n) ......

Calculus - yes! tnk u ok? It's actually (x->0.) Find the limit of cot(x)-csc(...

calculus help - consider lim -->0^+ 1)sin(4x)/sin(3x) find the limit using a ...

Calculus-Limits - Okay, i posted this question yesterday, however, I did not ...

Calc Limits - lim (1+x)^1/x. Give an exact answer. x->0 This reads: The ...

Calculus - L'Hospital's Rule Lim(lnx)^(x-1) x->1+ This is what I did so far...