Homework Help: chem/math

Posted by help on Thursday, October 28, 2010 at 9:53pm.

I need to fid the activation energy but i forgot how to solve for Ea

4.58*10^-15=e^(Ea/2537.02)

can you show the work thank you

chem/math - jai, Thursday, October 28, 2010 at 10:05pm
take the ln of both sides:
ln [4.58*10^-15] = ln [e^(Ea/2537.02)]
*since ln has a base of e, the term at the right side becomes:
ln [4.58*10^-15] = (Ea/2537.02)

now you solve for Ea. :)
chem/math - help, Thursday, October 28, 2010 at 10:19pm
thanks that helps alot

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