I need to fid the activation energy but i forgot how to solve for Ea
4.58*10^-15=e^(Ea/2537.02)
can you show the work thank you
take the ln of both sides:
ln [4.58*10^-15] = ln [e^(Ea/2537.02)]
*since ln has a base of e, the term at the right side becomes:
ln [4.58*10^-15] = (Ea/2537.02)
now you solve for Ea. :)
thanks that helps alot
To solve for the activation energy (Ea), you can use logarithms to isolate Ea in the equation:
4.58 * 10^-15 = e^(Ea/2537.02)
1. Take the natural logarithm (ln) of both sides to remove the exponential term. The natural logarithm is the inverse function of taking the exponential.
ln(4.58 * 10^-15) = ln(e^(Ea/2537.02))
2. Simplify the left side of the equation using the properties of logarithms.
ln(4.58) + ln(10^-15) = Ea/2537.02
3. Evaluate the logarithm of the constant on the left side.
ln(4.58) = 1.524187052
4. Rewrite the equation with the new values.
1.524187052 + ln(10^-15) = Ea/2537.02
5. Evaluate the logarithm of the exponential term on the right side.
ln(10^-15) = -34.65735903
6. Rewrite the equation with the new values.
1.524187052 - 34.65735903 = Ea/2537.02
7. Simplify the equation.
-33.13317198 = Ea/2537.02
8. Multiply both sides of the equation by 2537.02 to isolate Ea.
Ea = -33.13317198 * 2537.02
9. Calculate the value of Ea using a calculator or computer.
Ea ≈ -83,924.58313
Therefore, the activation energy Ea is approximately -83,924.58313.