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March 28, 2017

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I need to fid the activation energy but i forgot how to solve for Ea

4.58*10^-15=e^(Ea/2537.02)

can you show the work thank you

  • chem/math - ,

    take the ln of both sides:
    ln [4.58*10^-15] = ln [e^(Ea/2537.02)]
    *since ln has a base of e, the term at the right side becomes:
    ln [4.58*10^-15] = (Ea/2537.02)

    now you solve for Ea. :)

  • chem/math - ,

    thanks that helps alot

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