college Physics
posted by Lyn on .
Q. A force F = (3.99xi + 2.86yj) N acts on an object as it moves in the x direction from the origin to x = 4.45 m. Calculate the work done on the object by the force.
Attemp:
since we only consider x direction i multiplied 3.99 by 4.45 but it didn't work out.

work done is integral Fdotdx
INT (3.99x)dx= 1/2 3.99x^2 over limits, or
work= 1/2 3.99 (4.45)^2
I am assuming you are taking calculus. 
Thank You!!!