Posted by **Amy** on Thursday, October 28, 2010 at 8:41pm.

The captain sinks a ship located x distance away with a cannon located on the top of a cliff that is 65m high. if the cannon ball has a velocity of 55m/s and the captain sinks the ship, how far was the ship from the base of the cliff.

I got 731.5 meters. is that right?

- Physics -
**MathMate**, Thursday, October 28, 2010 at 10:33pm
ASSUMING the cannon direction was horizontal, and neglect air resistance.

Time to free-fall 65m, t:

65 = ut+(1/2)gt²

u=0 (initial vertical velocity)

t=√(65*2/9.81)=3.64 s.

Horizontal distance = 3.64*ux

= 3.64*55

= 200.2m

Can you explain how you got 731.5m?

- Physics -
**bobpursley**, Thursday, October 28, 2010 at 10:34pm
I do not know in what direction the cannon was aimed, particularly, the elevation.

Assuming horizontal, and no one would shoot a cannon horizontal, but

time to fall 65m...

65=1/2 g t^2 or

t= sqrt 130/9.8= 3.64sec

distance horizontal= 55m/s*3.64 which is not your answer.

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