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October 31, 2014

October 31, 2014

Posted by **mike** on Thursday, October 28, 2010 at 8:16pm.

- algebra -
**jai**, Thursday, October 28, 2010 at 9:47pmfirst, represent unknowns using variables:

let x = price of hamburger

let y = price of hotdogs

set up equation:

(1) 6x + 3y = 27

(2) 5x + y = 18.75

there are several ways to solve this,, but id we use substitution method,,

choose an equation (in this case, equation (2)),, then express one of the variables in terms of the other,, thus if we express y in terms of x:

5x + y = 18.75

y = 18.75 - 5x

then we substitute this to equation (1):

6x + 3y = 27

6x + 3(18.75 - 5x) = 27

now simplify this and solve for x. after that substitute this x to either equations to get y.

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