Posted by **Anonymous** on Thursday, October 28, 2010 at 6:16pm.

A ball of mass .15 kg and a radius of .24 m is at the top of a 3.5 m tall hill with a 25 degree incline. What is the velocity of the ball as it reaches the bottom of the hill if it (a) rolls without slipping? (b)slips without rolling?

- physics -
**drwls**, Thursday, October 28, 2010 at 6:41pm
The height of the hill H tells you the potential energy per unit mass, gH.

This equals the kinetic energy at the bottom in both cases.

In case (b), the KE per unit mass is just V squared.

In acase (a), rotational kinetic energy must be included, and the velocity will be less.

You will need to use the equation for the moment of inertia of a sphere.

We wll be happy to critique your work.

- physics -
**Anonymous**, Thursday, October 28, 2010 at 7:25pm
Ok thanks! I think I figured out the equation..

you use mgh=1/2mv^2 + 1/2Iw^2 and solve for v. right?

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