Posted by Jean on Thursday, October 28, 2010 at 5:57pm.
find th quadratic fuction that has a vertix of (8.3) and whose graph goest throught the point (6, 395)

College Algebra  Henry, Friday, October 29, 2010 at 11:57pm
V(8 , 3) , P(6 , 395).
Y = a(x  h)^2 + K.
395 = a(6  8)^2 + (3),
395 = 196a  3,
196a = 395 + 3,
196a = 392,
a = 392 / 196 = 2.
Eq: y = 2(x  8)^2  3(Vertex form).
This parabola opens downward, because a < 0.
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