Posted by **Jean** on Thursday, October 28, 2010 at 5:57pm.

find th quadratic fuction that has a vertix of (8.-3) and whose graph goest throught the point (-6, -395)

- College Algebra -
**Henry**, Friday, October 29, 2010 at 11:57pm
V(8 , -3) , P(-6 , -395).

Y = a(x - h)^2 + K.

-395 = a(-6 - 8)^2 + (-3),

-395 = 196a - 3,

196a = -395 + 3,

196a = -392,

a = -392 / 196 = -2.

Eq: y = -2(x - 8)^2 - 3(Vertex form).

This parabola opens downward, because a < 0.

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