chem
posted by gie on .
How many grams of chlorine gas are present in a 150. liter cylinder of chlorine held at a pressure of 1.00 atm and 0.0 °C?

Use PV = nRT, solve for n = moles and convert moles to grams.

using PV=nRT...
n=PV/RT
= 1 atm*150L/0.08206 (atm*L/mol*K)
= 150/22.40238 mol
= 6.71 mol Cl
THEN...
6.71 mol Cl x 35.45gCl/1mol Cl = 237 g Cl 
70x^2 ClNa2

its 474g...your answer is so very wrong!!