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September 16, 2014

September 16, 2014

Posted by **Calculus** on Thursday, October 28, 2010 at 1:17pm.

- Math Help Please -
**MathMate**, Thursday, October 28, 2010 at 1:36pmLet the pipe go from R (refinary) to P over a distance of 6-x km.

The distance (under water) from P to S (storage) is therefore √(x²+2²).

The total cost, C

C = C1(6-x) + C2 (√(x²+2²))

where C1=cost on land

C2 = cost under water, /km

Differentiate C(x) with respect to x and equate to zero for a local minimum.

Solve for x.

- Math Help Please -
**Andrew**, Sunday, November 11, 2012 at 3:56pmx=4.4

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