Thursday

November 27, 2014

November 27, 2014

Posted by **Calculus** on Thursday, October 28, 2010 at 1:17pm.

- Math Help Please -
**MathMate**, Thursday, October 28, 2010 at 1:36pmLet the pipe go from R (refinary) to P over a distance of 6-x km.

The distance (under water) from P to S (storage) is therefore √(x²+2²).

The total cost, C

C = C1(6-x) + C2 (√(x²+2²))

where C1=cost on land

C2 = cost under water, /km

Differentiate C(x) with respect to x and equate to zero for a local minimum.

Solve for x.

- Math Help Please -
**Andrew**, Sunday, November 11, 2012 at 3:56pmx=4.4

**Answer this Question**

**Related Questions**

Math - An oil refinery is located 1 km north of the north bank of a straight ...

Calc - An oil refinery is located on the north bank of a straight river that is ...

Calculus - Can anyone help me with these two optimization problems? A boat ...

chemistry - what are the gases that constitute the air in a refinery Are you ...

physics - A 410-m-wide river has a uniform flow speed of 2.0 m/s through a ...

Geometry - A new pipeline is being constructed to re-route its oil flow around ...

science - why archaeologist and environmental scientists were worried about the ...

Pre Calc - From 2 points 400 yards apart on the bank of a straight river flowing...

math - Tema Oil Refinery ( TOR ) is the only company mandated to refine crude ...

MATH - It is a well-known fact that homing pigeons fly faster over land than ...