Posted by Calculus on Thursday, October 28, 2010 at 1:17pm.
Let the pipe go from R (refinary) to P over a distance of 6-x km.
The distance (under water) from P to S (storage) is therefore √(x²+2²).
The total cost, C
C = C1(6-x) + C2 (√(x²+2²))
where C1=cost on land
C2 = cost under water, /km
Differentiate C(x) with respect to x and equate to zero for a local minimum.
Solve for x.
x=4.4
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