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December 20, 2014

December 20, 2014

Posted by **help** on Thursday, October 28, 2010 at 12:53pm.

f(x)= (x^2-4)/(x^2+4), [-4, 4]

- calculus -
**Calculus**, Thursday, October 28, 2010 at 1:32pmfind f'(x)

set f'(x)=0 to find the critical values.

when looking for the min and max include the intervals with the critical numbers

f'(x)= [2x(x^2+4)-(2x(x^2-4)]/[(x^2+4)^2]

simplify....

and set equal to zero

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