Sunday

April 20, 2014

April 20, 2014

Posted by **saad** on Thursday, October 28, 2010 at 11:30am.

- college -
**jai**, Thursday, October 28, 2010 at 11:41amsince it's not factorable, we use quadratic formula:

x = [-b +- sqrt(b^2 -4ac)]/(2a)

where a=3, b=1, and c=1

substituting:

x = [-1 +- sqrt(1^2 - 4*3*1)]/(2*3)

x = [-1 +- sqrt(-11)]/6

thus

x = [-1 + i*sqrt(11)]/6 ; and

x = [-1 - i*sqrt(-11)]/6

*note: i = sqrt(-1)

hope this helps~

- college-typo -
**jai**, Thursday, October 28, 2010 at 11:44amoops, some typo:

x = [-1 + i*sqrt(11)]/6 ; and

x = [-1 - i*sqrt(11)]/6

**Related Questions**

college algebra - Could you help me with this long division problem of a ...

Math help please check - Add or Subtract for #3-4 3. (2x2 + 6x + 1) + (–7x2 + ...

algebra - Can someone please explain What polynomial has a graph that passes ...

Math - How do I factor 3x2 =4x +1 and 3x2-2x-8

math - 36=6 x 6 ^ ^ 3x2 3x2 Answer: 3^2 x 2^2

college math - find the vertex and graph of y=.3x2+1.8x-2

College Algebra - let g(x) = 17x3 - 3x2 + 14x. What is the degree of this ...

math - Determine the remainder of the following polynomial divisions: (2 marks) ...

College Algebra - Let g(x) = 17x3 - 3x2 + 14x. Find the sum of all of the ...

Algebra2 - Complete parts a – c for each quadratic function. a. Find the y-...