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February 1, 2015

February 1, 2015

Posted by **saad** on Thursday, October 28, 2010 at 11:30am.

- college -
**jai**, Thursday, October 28, 2010 at 11:41amsince it's not factorable, we use quadratic formula:

x = [-b +- sqrt(b^2 -4ac)]/(2a)

where a=3, b=1, and c=1

substituting:

x = [-1 +- sqrt(1^2 - 4*3*1)]/(2*3)

x = [-1 +- sqrt(-11)]/6

thus

x = [-1 + i*sqrt(11)]/6 ; and

x = [-1 - i*sqrt(-11)]/6

*note: i = sqrt(-1)

hope this helps~

- college-typo -
**jai**, Thursday, October 28, 2010 at 11:44amoops, some typo:

x = [-1 + i*sqrt(11)]/6 ; and

x = [-1 - i*sqrt(11)]/6

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