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Posted by on Thursday, October 28, 2010 at 11:05am.

Find the area under the curve below from x = 0 to x = 2. Give your answer correct to 3 decimal places.
y = 2x - x2

  • calc - , Thursday, October 28, 2010 at 11:15am

    is y = 2x - x^2 the function given? if it is,
    area under the curve means the integral at these particular bounds,, first you have to recall how to integrate:
    for ax^n (a is constant), add 1 to the power, then this n+1 must be divided:
    integral (ax^n) = (a)[x^(n+1)]/(n+1)
    thus for 2x - x^2, we do it separately (by term):
    integral 2x = 2x^(1+1)/(1+1) = x^2
    integral x^2 = x^(2+1)/(2+1) = (x^3)/3
    then evaluate x^2 - (x^3)/3 from 0 to 2.

    hope this helps. :)

  • calc - , Thursday, October 28, 2010 at 11:18am

    **i'll just retype it to make the integration part clearer:
    integral 2x = [2x^(1+1)]/(1+1) = (2x^2)/2 = x^2
    integral x^2 = [x^(2+1)]/(2+1) = (x^3)/3

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