posted by justin on .
What volume of 0.0482 M Ba(OH)2 is required to neutralize exactly 16.10 mL of 0.141 M H3PO4? Phosphoric acid contains three acidic hydrogens.
Write the equation and balance it.
3Ba(OH)2 + 2H3PO4 ==> Ba3(PO4)2 + 6H2O
moles H3PO4 given = M x L = ??
Using the coefficients in the balancd equation, convert moles H3PO4 to moles Ba(OH)2.
Now M Ba(OH)2 = moles Ba(OH)2/L Ba(OH)2.
You have M and moles, solve for L.