Posted by Courtney on .
a cylinder has a radius of 3cm and a length of 10cm every dimention of the cylinder is multiplied by 3 to form a new cylinder how is the ratio of the volumes related the ratio of corresponding dimensions? how would i do this?

Math 8th grade algerbra 
jai,
Volume of cylinder = area of the base * height , or
V = pi*(r^2)*h
V,original = pi*(3^2)(10)
*you solve for this.
then for the new one,
r,new = 3*3 = 9
h,new = 3*10 = 30
V, new = pi*(9^2)(30)
you solve also for this.
then compare their volumes, find:
(V,new)/V
so there,, hope this helps~ :) 
Math 8th grade algerbra 
Courtney,
Thank you

Math 8th grade algerbra 
Courtney,
is the answer 27?

Math 8th grade algerbra 
jai,
yes,, (V,new)/V = 27,,
and ration of dimensions is 3 (because it is tripled according to problem)
now, how is 27 related to 3? 
Math 8th grade pre algerbra 
Anonymous,
Y=5x;(15, 3)

Math 8th grade algerbra 
Christine,
How is the ratio of the volumes related to the ratio of corresponding dimensions?