Posted by Courtney on Wednesday, October 27, 2010 at 11:00pm.
a cylinder has a radius of 3cm and a length of 10cm every dimention of the cylinder is multiplied by 3 to form a new cylinder how is the ratio of the volumes related the ratio of corresponding dimensions? how would i do this?
Math 8th grade algerbra - jai, Wednesday, October 27, 2010 at 11:09pm
Volume of cylinder = area of the base * height , or
V = pi*(r^2)*h
V,original = pi*(3^2)(10)
*you solve for this.
then for the new one,
r,new = 3*3 = 9
h,new = 3*10 = 30
V, new = pi*(9^2)(30)
you solve also for this.
then compare their volumes, find:
so there,, hope this helps~ :)
Math 8th grade algerbra - Courtney, Wednesday, October 27, 2010 at 11:10pm
Math 8th grade algerbra - Courtney, Wednesday, October 27, 2010 at 11:17pm
is the answer 27?
Math 8th grade algerbra - jai, Wednesday, October 27, 2010 at 11:35pm
yes,, (V,new)/V = 27,,
and ration of dimensions is 3 (because it is tripled according to problem)
now, how is 27 related to 3?
Math 8th grade pre algerbra - Anonymous, Friday, October 29, 2010 at 7:27pm
Math 8th grade algerbra - Christine, Thursday, September 25, 2014 at 11:40am
How is the ratio of the volumes related to the ratio of corresponding dimensions?
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