Posted by **Courtney** on Wednesday, October 27, 2010 at 11:00pm.

a cylinder has a radius of 3cm and a length of 10cm every dimention of the cylinder is multiplied by 3 to form a new cylinder how is the ratio of the volumes related the ratio of corresponding dimensions? how would i do this?

- Math 8th grade algerbra -
**jai**, Wednesday, October 27, 2010 at 11:09pm
Volume of cylinder = area of the base * height , or

V = pi*(r^2)*h

V,original = pi*(3^2)(10)

*you solve for this.

then for the new one,

r,new = 3*3 = 9

h,new = 3*10 = 30

V, new = pi*(9^2)(30)

you solve also for this.

then compare their volumes, find:

(V,new)/V

so there,, hope this helps~ :)

- Math 8th grade algerbra -
**Courtney**, Wednesday, October 27, 2010 at 11:10pm
Thank you

- Math 8th grade algerbra -
**Courtney**, Wednesday, October 27, 2010 at 11:17pm
is the answer 27?

- Math 8th grade algerbra -
**jai**, Wednesday, October 27, 2010 at 11:35pm
yes,, (V,new)/V = 27,,

and ration of dimensions is 3 (because it is tripled according to problem)

now, how is 27 related to 3?

- Math 8th grade pre algerbra -
**Anonymous**, Friday, October 29, 2010 at 7:27pm
Y=5x;(15, -3)

- Math 8th grade algerbra -
**Christine**, Thursday, September 25, 2014 at 11:40am
How is the ratio of the volumes related to the ratio of corresponding dimensions?

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