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October 1, 2014

October 1, 2014

Posted by **HELPP** on Wednesday, October 27, 2010 at 10:58pm.

- Ap calculus -
**MathMate**, Thursday, October 28, 2010 at 10:16amEvaluate g(π/3)=-1/π (check!)

Therefore the tangent passes through the point P1=(x1,y1)=(π/3,-1/π).

Find the derivative g'(x), and hence the slope at P1.

The tangent line is given by

L1: y-y1 = m(x-x1)

where m=g'(π/3), and (x1,y1) are the coordinates of P1 given above.

If you need help finding g'(x), please post.

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