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March 26, 2017

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Find the equation of the tangent line to the curve g(X)= 2cos(2X)/(3X) at the point x= pi/3

  • Ap calculus - ,

    Evaluate g(π/3)=-1/π (check!)
    Therefore the tangent passes through the point P1=(x1,y1)=(π/3,-1/π).
    Find the derivative g'(x), and hence the slope at P1.
    The tangent line is given by
    L1: y-y1 = m(x-x1)
    where m=g'(π/3), and (x1,y1) are the coordinates of P1 given above.
    If you need help finding g'(x), please post.

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