Posted by HELPP on Wednesday, October 27, 2010 at 10:58pm.
Evaluate g(π/3)=-1/π (check!)
Therefore the tangent passes through the point P1=(x1,y1)=(π/3,-1/π).
Find the derivative g'(x), and hence the slope at P1.
The tangent line is given by
L1: y-y1 = m(x-x1)
where m=g'(π/3), and (x1,y1) are the coordinates of P1 given above.
If you need help finding g'(x), please post.
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