Posted by **help** on Wednesday, October 27, 2010 at 10:38pm.

Use a linear approximation (or differentials) to estimate the given number

(2.001)^5

- calculus -
**MathMate**, Thursday, October 28, 2010 at 10:20am
Let y=x^{5},

y'=5x^{4}.

y(x+h)=y(x)+y'(2)*h (approximately)

Therefore, an approximation to y(2.001) is

y(2.001)

=y(2)+y'(2)*0.001

=2^5 + 5(2)^4*0.001 (approximately)

- calculus -
**sci**, Wednesday, December 8, 2010 at 10:13pm
approximate 4 square root of 15.8

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