Friday
March 24, 2017

Post a New Question

Posted by on .

Use a linear approximation (or differentials) to estimate the given number

(2.001)^5

  • calculus - ,

    Let y=x5,
    y'=5x4.
    y(x+h)=y(x)+y'(2)*h (approximately)
    Therefore, an approximation to y(2.001) is
    y(2.001)
    =y(2)+y'(2)*0.001
    =2^5 + 5(2)^4*0.001 (approximately)

  • calculus - ,

    approximate 4 square root of 15.8

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question