Posted by Elimination method PLEASE HELP on .
3x+4y=5
6x+8y=10

math/algebra 
jai,
(1) 3x+4y=5
(2) 6x+8y=10
to solve using elimination, you have to multiply a factor into the equation so that when you add/combine them, one of the variables gets eliminated or canceled out,,
here, if you want to cancel out x, what do you need to multiply to equation (1) so that if added to 6x it becomes zero? 
math/algebra 
find the slope if it exists,
i don't understand could you be more simpler please. I have been having a really hard time with this crap

math/algebra 
jai,
oh alright then.
(1) 3x + 4y = 5
(2) 6x + 8y = 10
if you want to cancel out x, you need to multiply 2 to equation (1) so that if added to 6x it becomes zero:
2(3x+4y=5) becomes 6x  8y = 10
then add this to equation (2):
6x  8y = 10
6x + 8y = 10
oh, it turned out both x and y AND the constant to become zero,, that only means that the line are coinciding > they have infinite solutions since there are equivalent (or they are the same)
so there,, hope this helps~ :) 
math/algebra 
find the slope if it exists,
please help me

math/algebra 
heeeellllpppppp,
does that mean there is no solution/

math/algebra 
jai,
oh sorry.
what did you not understand?
these two equations are coinciding,, thus, any point that satisfies the equation is a solution,,
coinciding means, they overlap, they are the same,, here, try to look at the second equation:
6x+8y=10
if you simplify this by dividing every term by 2, you will get
3x+4y=5 or the first equation!
therefore they are the same and has infinite solutions. :) 
math/algebra 
jai,
no,, they have INFINITE solutions,, any point that will satisfy either equations is a solution,, :)