How many atoms of mercury are present in 5.4 cubic cm of liquid mercury? The density of mercury is 13.55g/cc.
mass Hg = volume x density
Then convert to moles.
Then remember there are 6.022E23 atoms for every mole.
I still don't get how to do this! HELP ME!!!
Of course! I'm here to help. Let's break it down step by step:
1. First, we need to calculate the mass of the liquid mercury in the given volume. The formula for mass is mass = volume × density. In this case, the volume is given as 5.4 cubic cm and the density of mercury is given as 13.55 g/cc (grams per cubic centimeter).
So, mass of mercury = 5.4 cc × 13.55 g/cc = 73.17 grams.
2. Next, we need to convert the mass of the liquid mercury to moles. To do this, we need to know the molar mass of mercury (Hg). The molar mass of an element is the mass of one mole of that element, and it can be found on the periodic table.
The molar mass of mercury (Hg) is approximately 200.59 grams/mole.
So, moles of mercury = mass of mercury / molar mass of mercury = 73.17 g / 200.59 g/mol ≈ 0.365 moles.
3. Finally, we need to determine the number of atoms in 0.365 moles of mercury. Avogadro's number tells us that there are 6.022 × 10^23 atoms in one mole of any substance.
So, number of atoms of mercury = moles of mercury × Avogadro's number = 0.365 moles × 6.022 × 10^23 atoms/mole ≈ 2.2 × 10^23 atoms.
Therefore, there are approximately 2.2 × 10^23 atoms of mercury in 5.4 cubic cm of liquid mercury.
I hope this explanation helps you understand the process! Let me know if you have any further questions.
You won't learn how to do it with me doing the work for you.
Substitute the numbers into the equations I've written (and post your ork) until you get stuck, then post what you don't understand about the next step. I shall be happy to help you through it. Help is the key word here.