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math!!!!!!! help 3

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a water cooler contains 5 gallons of water.if drink 3/5 gallon for each of the next 6 days how many gallons will be left in water cooler at the end of the sixth?

  • math!!!!!!! help 3 - ,

    5-(3/5*6)

  • math!!!!!!! help 3 - ,

    is it 3 3/5

  • math!!!!!!! help 3 - ,

    3 3/5 was the part in parenthesis. So now do 5-3 3/5.

  • math!!!!!!! help 3 - ,

    Jen told you to subtract. You didn't do that.

  • math!!!!!!! help 3 - ,

    first multiply 3/5 by 6
    3/5 * 6 = 18/5
    then convert 5 into fraction such that its denominator is 5:
    5 = 25/5
    therefore:
    (25-18)/5 = 7/5 or 1 2/5 gallons

    so there,, :)

  • math!!!!!!! help 3 - ,

    Jai, please allow the students a chance to attempt the problems on their own with our guidance.

  • math!!!!!!! help 3 - ,

    i have a question for jen

  • math!!!!!!! help 3 - ,

    Yes?

  • math!!!!!!! help 3 - ,

    oh sorry.
    alright, Jen.

  • math!!!!!!! help 3 - ,

    well i got stuck because i did 3/5*6/1 and i got 18/5 then i did 18 divied by 5 and got 3 3/5 so is 3 3/5 the answer

  • math!!!!!!! help 3 - ,

    3 3/5 gallons is how much water you drank after 6 days. 6 days * 3/5 gallons each day is 3 3/5. BUT..the question is how much water is left. If you started with 5 gallons, now you must do 5-3 3/5 for your answer.

  • math!!!!!!! help 3 - ,

    ok so the answer would then be 1 2/5s gallons?

  • math!!!!!!! help 3 - ,

    Yes! Good job, Niki!

  • math!!!!!!! help 3 - ,

    THANK YOU 4 helping math isent my strong suit but it helps to be walked through it instead of just given the answer i greatly appretiate your time

  • math!!!!!!! help 3 - ,

    that did not help me

  • math!!!!!!! help 3 - ,

    en 100 platos cuantos litros de agua dentra

  • math!!!!!!! help 3 - ,

    You first need to find out how many gallons would be drank after 6 days, so you multiply 3/5 * 6 to get 18/5. Then you subtract 18/5 from the original 5 gallons so 5 - 18/5. You have to make equivalent fractions so you put the 5 over one, and multiply the numerator and denominator by the same thing so 5*5 and 1*5. This give you a new fraction of 25/5, which was the original amount of 5 gallons. Then you subtract the original amount from the amount drank after 6 days, so 25/5 - 18/5= 7/5. Then you make the improper fraction into a mixed number, divide 7 by 5 to get 2 1/5 gallons.

  • math!!!!!!! help 3 - ,

    Start: 5 gallons of water
    Drank: 3/5 each day for 6 days, or 3/5 x
    6/1=18/5
    Subtract what was drank from the 5 gallons
    2 ways to do this:
    IMPROPER FRACTION:
    5/1 minus 18/5=25/5-18/5=7/5 or 1 2/5

    MIXED FRACTION WHERE WHOLE NUMBER IS RENAMED:
    5 minus 3 3/5 = 4 5/5 - 3 3/5 = 1 2/5

    Started with 5 gallons, drank 3 3/5 gallons, so 1 2/5 gallons was left at the end of 6 days.

  • math!!!!!!! help 3 - ,

    Start: 5 gallons of water
    Drank: 3/5 each day for 6 days, or 3/5 x
    6/1=18/5
    Subtract what was drank from the 5 gallons
    2 ways to do this:
    IMPROPER FRACTION:
    5/1 minus 18/5=25/5-18/5=7/5 or 1 2/5

    MIXED FRACTION WHERE WHOLE NUMBER IS RENAMED:
    5 minus 3 3/5 = 4 5/5 - 3 3/5 = 1 2/5

    Started with 5 gallons, drank 3 3/5 gallons, so 1 2/5 gallons was left at the end of 6 days.

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