posted by K.C .
Find an equation of the line containing the points (8,-6) and (8, -4)
so far i've tried y-y1=m(x+x1) but currently cannot get the answer....T-T
the answer is suppose to be x=8
plz show the work so i can study form it and do it myself the next time... thnx in advance
did you not notice that the slope is undefined?
(slope = (-4 + 6)/(8-8) = 2/0)
so you have a vertical line.
All vertical lines are of the form x = ? , where the ? is simply the x coordinate of any point on the line
Thus x = 8
btw, a horizontal line would be of the form
y = ? , where ? is the y coordinate of any point on the line , (all the y's would be the same).
If you really insist on using your method, you could go ...
y - (-6) = (2/0)(x - 8)
then 0(y+6) = 2(x-8)
0 = x-8
x = 8
but that is rather silly
slope = m = (Y2-Y1)/(X2-X1) = (-4-8)/(8-8)
Oh my, we have a problem, the slope is undefined because of zero denominator.
The line with infinite slope goes straight up, constant x
so the solution is
x = 8