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October 25, 2014

October 25, 2014

Posted by **Alex** on Wednesday, October 27, 2010 at 8:51pm.

- Physics HELP!!! -
**Damon**, Wednesday, October 27, 2010 at 8:58pmKinetic energy = (1/2) I w^2

velocity of surface of ball = w r = .2 w = 3

so

w = 3/.2 = 15 radians/second

now potential energy at top = kinetic energy at bottom

so

m g h = (1/2) (2/3) m r^2 (15)^2

m cancels, g = 9.8

h = (1/3) (.04)(225/9.8)

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