Please help me how you get the answer. PLEASE I NEED HELP. A triangle sail has a perimeter of 25 m. Side a is 2 m shorter than twice side b, and side c is 3 m longer than side b. Find the length of each side. Thank you ver much for helping me

what is the ritao of the measures of side bc to side rs in simplest form

To solve this problem, we will use the information given and form equations based on the relationships between the sides of the triangle.

Let's assign variables to each side of the triangle:
- Side a: length of side a
- Side b: length of side b
- Side c: length of side c

From the problem statement, we have three pieces of information:

1. The perimeter of the triangle is 25 m:
Perimeter = a + b + c = 25

2. Side a is 2 m shorter than twice side b:
a = 2b - 2

3. Side c is 3 m longer than side b:
c = b + 3

We now have a system of three equations with three unknowns.

To find the values of a, b, and c, we can solve this system of equations using substitution or elimination. Let's use the substitution method:

First, substitute the expressions for a and c from equations 2 and 3 into equation 1:
(2b - 2) + b + (b + 3) = 25

Simplifying the equation:
4b + 1 = 25

Next, isolate b by subtracting 1 from both sides:
4b = 24

Divide both sides by 4 to solve for b:
b = 6

Now that we have the value of b, we can substitute it back into equations 2 and 3 to find the values of a and c:

Using equation 2:
a = 2b - 2
a = 2 * 6 - 2
a = 12 - 2
a = 10

Using equation 3:
c = b + 3
c = 6 + 3
c = 9

Therefore, the lengths of the sides of the triangle are as follows:
Side a = 10 m
Side b = 6 m
Side c = 9 m

So, the lengths of the sides of the triangle are 10 m, 6 m, and 9 m.

a+b+c=25

a=2b-2
c=b+3

a+b+c=25
(2b-3)+b+(b+3)=25 solve for b, then solve for a, and c