For the reaction SO3(g)---> SO2(g) + 1/2 O2(g), Kc= 16.7 at 1000 K. What is the value of Kc at 1000 K for the reaction
2 SO2 (g) + O2(g)---> 2 SO3(g)?
When you double the coefficients, K is squared; therefore, Kc2 = 16.72 = ??
To find the value of Kc at 1000 K for the reaction 2 SO2 (g) + O2(g) ---> 2 SO3(g), we can use the relationship between the Kc values of directly related reactions.
First, let's consider the given reaction: SO3(g) ---> SO2(g) + 1/2 O2(g).
The forward reaction of the given reaction is the reverse reaction of the desired reaction. Therefore, the Kc value for the desired reaction can be obtained by taking the reciprocal of the Kc value for the given reaction.
Reciprocal of Kc = 1/Kc
So, to find the value of Kc for the reaction 2 SO2 (g) + O2(g) ---> 2 SO3(g), we need to calculate 1/Kc.
Given, Kc = 16.7 for the reaction SO3(g) ---> SO2(g) + 1/2 O2(g) at 1000 K.
Calculating 1/Kc: 1/Kc = 1/16.7
Therefore, the value of Kc at 1000 K for the reaction 2 SO2 (g) + O2(g) ---> 2 SO3(g) is approximately 0.060.