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physics 111

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A ball of mass 0.120 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.600 m. What impulse was given to the ball by the floor?

answer in kg·m/s

  • physics 111 -

    figure the velocity at impact, and leaving impact.

    at impact, velocity= sqrt 2gh
    returning, velocity= sqrt 2gh*.6 opposite direction

    change velocity= Vi-Vf=sqrt2gh+sqrt(2gh*.6)

    impulse= mass*changevelocity, upward direction.

  • physics 111 -


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